Res/342 Ii

There are quintuple standards to the supposal studying. The beginning(a) t superstar is to posit the cryptograph & alterative supposal, the minute step is dumbfounding the dainty appreciate, third step is to exercise the tryout statistic, the fourth step is to compare the test to the lively tally and the fifth ground is the results. The team allow crumple the stack away selective in conditionation to decide if 10 part or more(prenominal) of Central case Bank checking account customers in metropolis 1and 2 is use its ATM. timber one: situate the hypothesis. The futile hypothesis is the affirmation that is believed to be true and is shown as? H?_0. The Alternative Hypothesis maybe true if the Null hypothesis is rid ofed and is shown as H_1. To show the hypothesis from higher up in this numerical form would be this: H_0 ? ? .10 H_1 ? < .10 Step twain: bring forth the critical value. To be able to find the Z critical value, one must know the consequence value for this expression of a one-tailed test a implication level of 0.05 will be apply which gives a Z critical value of 1.753. importation Level is 0.05 Z minute Value is 1.753 worsen H_(0 )if z less(prenominal) than 1.

753 otherwise do not reject H_0 Step Three: Calculate the test Statistic. The formula used and cream is shown below t=(¯x_1-¯x_2)/(?((s_1^2)/n_1 )+(s_2^2)/n_2 ) City 1City 2 ¯x_= 9.37¯x_ = 11 n=16n=16 s=25s=20 t=(9.37-11)/(?(?25?^2/18)+?25?^2/18) (-1.63)/(?(625/16)+625/16) (-1.63)/?(39.06+39.06) (-1.63)/?78.12 (-1.63)/8.84 .18 Step 4: canvass the test to the critical value. Since the t = 0.18 Step basketball team: State the results. Since z is less than 1.753 H_0 is not rejected.If you want to run a full essay, guild it on our website: Ordercustompaper.com

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